Question

x2-6x-6=0

Answer 1

we literally just told you how to solve these problems in the last one.

For \(f(x)=ax^2+bx+c=0\) \[x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}\]Is there something you don't understand? If so just ask! We're not here to do other peoples homework for them!

Answer 2

ummm ur being rude the other one was easy this one has me confused, and just givin me a formula where i can miss up isnt helpin me -_-

Answer 3

what answer did you get when you tried plugging into the formula?

Answer 4

\[\left( x-3 \right)^{2}-3^{2}-6=0\]
\[\left( x-3 \right)^{2}-15=0\]
\[\left( x-3 \right)^{2}=15\]
\[\left( x-3 \right)=\pm \sqrt{15}\]
\[x =\pm \sqrt{15}+3\]
\[x =\sqrt{15}+3\] or \[x =3-\sqrt{15}\]