Question

H9P1: RESPONSE TO A DELAYED IMPULSE

A=2/π=0.64 , t=9.0s.

At t=0 the state is: vC(0)=0.0 and iL(0)=1.0.

B. At the initial time what is the total energy, in Joules, stored in the circuit?
C. At the time just before the impulse happens t=9.0− what is the total energy, in Joules, stored in the circuit?
E. At the time just before the impulse happens what is the voltage vC(9.0−), in Volts, across the capacitor?

Answer 1

B) n C) total energy is ½*L*iL^2 (in Joules)
E) vC = -L*2*pi*f*sin(2*pi*f*t)

Answer 2

Lab 9
Figure 2. Boost converter

Answer 3

what is the ans. of Lab 9
Figure 2. Boost converter

Answer 4

double click on square part of d diagram and change the duty cycle % to 58 and change it
after that click on TRAN option on top-left of diagram n without closing d dialog box click check :)

Answer 5

H10P3: An L Network

Cmatch=?

Lmatch=?

Answer 6

giv me the value of f for this question pls

Answer 7

R1=1000.0Ω.
R2=50.0Ω
f=630.0kHz

Answer 8

Lmatch - 55.05
Cmatch - 1159.13

Answer 9

Plzzz Help me.
H10P3: An L Network
if f=630.0kHz
Cmatch=?????
Lmatch=?????

Answer 10

Lmatch - 55.05 is correct bt
Cmatch - 1159.13 in incorrect

Answer 11

?

Answer 12

w = 2*pi*f
Cmatch = R1R2/(w*sqrt(R1R2 – R2^2))
or
Cmatch = 1/(w*sqrt(R1R2 – R2^2))

calculate n see wich 1 is correct :)

Answer 13

pi=?

Answer 14

3.14

Answer 15

R1=1000.0Ω.
R2=50.0Ω.
f=630.0kHz


w= 2*pi*f = 3956.4

but according to this formula

Cmatch = R1R2/(w*sqrt(R1R2 – R2^2)) = 0.05798598066

Cmatch = 1/(w*sqrt(R1R2 – R2^2)) = 1.159719613*10^-6

both are incorrect

Answer 16

w=3958406.744
Cmatch = 1/(w*sqrt(R1R2 – R2^2)) = 1159.131685
Cmatch = R1R2/(w*sqrt(R1R2 – R2^2)) =57956584.23 (surely wrong dis one)

Answer 17

haa yr

Answer 18

log out from ur edx account and den login again and den paste dis ans in ur Cmatch ans 1159.131685 n den chek

Answer 19

HOW TO CHECK BOOST CONVERTOR MY ANSWER IS STILL NOT CORRECT

Answer 20

after converting duty cycle % to 58
do transient analysis of ckt
and den directly chek it

Answer 21

At the time just before the impulse happens what is the voltage vC(9.0−), in Volts, across the capacitor?
if L=70H, C=5.79mF, t=9sec , iL(0)=1 plzzz tell me the answer.....

Answer 22

v= -L*2*pi*f*sin(2*pi*f*t)
= -70*2*pi*0.25*sin(2*pi*0.25*9) = -109.95574