A box of transistor contains four that are defective and five are non-defective.How many ways can an inspector choose five transistors so that 4 are defective ?

Question

hba · Answer

$$\Huge{Help}$$

hba · Answer

@jiteshmeghwal9

hba · Answer

$$\Huge{Please \space help \space guys ?}$$

hba · Answer

Hints are helpful for me

hba · Answer

Please dont post the solution

sirm3d · Answer

choose all defective transistors and choose 1 among 5 good transistors.

jiteshmeghwal9 · Answer

Defective transistors--->4
Non-Defective transistors---->5
A/q,


@sirm3d 's reply :)

sirm3d · Answer

there's only one way to choose all 4 defective transistors.

jiteshmeghwal9 · Answer

He is right he posted before i post my reply :)

hba · Answer

$$\Huge{4 \space Defective }$$ $$\Huge{5 \space  non defective}$$

hba · Answer

What next ?

sirm3d · Answer

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