Question

A box of transistor contains four that are defective and five are non-defective.How many ways can an inspector choose five transistors so that 4 are defective ?

Answer 1

\[\Huge{Help}\]

Answer 2

@jiteshmeghwal9

Answer 3

\[\Huge{Please \space help \space guys ?}\]

Answer 4

Hints are helpful for me

Answer 5

Please dont post the solution

Answer 6

choose all defective transistors and choose 1 among 5 good transistors.

Answer 7

Defective transistors--->4
Non-Defective transistors---->5
A/q,


@sirm3d 's reply :)

Answer 8

there's only one way to choose all 4 defective transistors.

Answer 9

He is right he posted before i post my reply :)

Answer 10

\[\Huge{4 \space Defective }\] \[\Huge{5 \space non defective}\]

Answer 11

What next ?