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A box contains 2 green,3 red and a black ball,Three balls are picked at random,In how many ways this can be done if a equal representation is desired ?
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@sirm3d
Hints please ?
C(2,1) for the green ball.
So C(3,1) for red
And C(1,1) for black ?
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And them multiply ?
yup. don't forget the multiplication rule for compound events.
Ok :)
Answer is 6
6 it is.
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Thanks i think i am understanding this :)
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