Question

H9P1: Response to a Delayed Impulse

L=20.0H and C=20.26mF.
A=2/π=0.64 Coulombs at time t=9.0s.

B. At the initial time what is the total energy, in Joules, stored in the circuit?

C. At the time just before the impulse happens t=9.0− what is the total energy, in Joules, stored in the circuit?

E. At the time just before the impulse happens what is the voltage vC(9.0−), in Volts, across the capacitor?

Answer 1

B) n C) total energy is ½*L*iL^2 (in Joules) (37.5)
E) vC = -L*2*pi*f*sin(2*pi*f*t)

Answer 2

B)37.5