Question

given sin A=3/5 and tan=-3/4. A and B are in QII. Find values of tan (A+B)

Answer 1

@ajoek tan(??) = -3/4

Answer 2

Ohh sorry...i mean...sin B=-3/4

Answer 3

ok by using the formula
tan(A+B) = tanA+tanB divided 1 - tanA*tanB

Answer 4

now put
tanA=sinA/cosA and tanB= sinB/cosB

Answer 5

u can find the values of cosines by using the formula
Sin^2A+Cos^2A=1

Answer 6

@ajoek right??

Answer 7

yes, agree