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OpenStudy (anonymous):
given sin A=3/5 and tan=-3/4. A and B are in QII. Find values of tan (A+B)
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OpenStudy (anonymous):
@ajoek tan(??) = -3/4
OpenStudy (anonymous):
Ohh sorry...i mean...sin B=-3/4
OpenStudy (anonymous):
ok by using the formula tan(A+B) = tanA+tanB divided 1 - tanA*tanB
OpenStudy (anonymous):
now put tanA=sinA/cosA and tanB= sinB/cosB
OpenStudy (anonymous):
u can find the values of cosines by using the formula Sin^2A+Cos^2A=1
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OpenStudy (anonymous):
@ajoek right??
OpenStudy (anonymous):
yes, agree
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