Question

f(x)= 1+7/x-4/x^2

vertical asymptote: x=0
horizontal asymptote: y=1

a) find where is the function increasing/decreasing?

b) find the local max/min values

c) find where the function is concave up/down, and the inflection points

Answer 1

\[f(x)=1+\frac{ 7 }{ x }-\frac{ 4 }{ x^2 }\]