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OpenStudy (anonymous):
what is the square root of 108
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OpenStudy (anonymous):
6√(3)
OpenStudy (anonymous):
can u show me how u solved that
jimthompson5910 (jim_thompson5910):
sqrt(108) sqrt(36*3) sqrt(36)*sqrt(3) sqrt(6^2)*sqrt(3) 6*sqrt(3) So sqrt(108) = 6*sqrt(3)
jimthompson5910 (jim_thompson5910):
The idea is to factor 108 into two numbers where one of the numbers is a perfect square (the largest perfect square possible)
jimthompson5910 (jim_thompson5910):
Then you break up the root and simplify
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OpenStudy (anonymous):
10.3923048454
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