Question

It won't let me fit my entire question in the box, so here's a link to the question: http://answers.yahoo.com/question/index;_ylt=AtD0n18xfcvsgGU5ly032Ubty6IX;_ylv=3?qid=20121111132012AAhfdXE

Answer 1

hey the page does not work

Answer 2

http://answers.yahoo.com/question/index;_ylt=AtD0n18xfcvsgGU5ly032Ubty6IX;_ylv=3?qid=20121111132012AAhfdXE there it is again hopefully it will work

Answer 3

i dont really feel confident with this question but im going to give it my best shot at it



okay



M = .05(t^4 - 18t^3 + 89t^2 - 32t +3680)

M=204 at a given time t

so .05(t^4 - 18t^3 + 89t^2 - 32t +3680)=204

if we rearrange

184 - 1.6 t + 4.45 t^2 - 0.9 t^3 + 0.05 t^4


Which answers A i think


The domain is the "height is wil reach"


So from 1995 to 2003
say 1993 = 0 and 2005 is 8


so t= from 0 to 8

==> 0=<t<=8
but t can carry on for ever...


For C i used a software as suggested so

{t -> -1.83891 - 4.72803 i}, {t -> -1.83891 + 4.72803 i}, {t ->
10.8389 - 5.05068 i}, {t -> 10.8389 + 5.05068 i}}


sub ing the first value in gave me close to 0 which was okay i suppose





IM NOT TOO SURE, i hate these kinds of questions... sorry