Question

I've had some difficulty with equation of the tangent line. F(X) = (-10x^2-3)/(4x+1) ; x = 0

Answer 1

Are you trying to find the equation of the tangent line?

Answer 2

yes i am. equation of the tangent line to the graph y = f(x) at the point on the graph where x has the inidcated valued

Answer 3

Ok. So you must find the slope of this line first, correct?

Answer 4

indeed, do i just plug it into the equation to find x then, find the derative, then plug it into the slope formula? y-y1 = m(x-x1)

Answer 5

well you must find the derivative of the original equation to find the slope of the tangent line. after derivating the original equation, plug in x=0. that will give you the slope of your tangent line at x=0

Answer 6

would f(x) be -3/1 at the slope when x =0

Answer 7

lemme do it..gimme a sec plz

Answer 8

Hmm, I got 12

Answer 9

let me do the problem again, generally i just did a quick overview of one part, but thank you! i appreciate it.

Answer 10

I'll do it again also