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Solve for x: √x+√(x-20)=10 NEED HELP!!!!
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Ok square both sides: \[2x-20+2\sqrt(x(x-20))=100\] Isolate the radical: \[2\sqrt{x(x-20)} = 120 -2x\] Square again: \[4(x-20)x=(120-2x)^2\] Expand terms: \[4x^2-80x=4x^2-480x+14400\] Subtract to simplify: \[400x-14400=0\] Factor out and divide x-36=0 So the answer is 36.
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