Question

Can someone tell me how to solve this please?
x^2-8ix-5i^2=0 It deals with imaginary numbers, so im not very sure how to solve this.

Answer 1

first, treat it just like any other variable except that it's just a number.
A straightforward solution is to apply: \[x= \frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\] right away.

Answer 2

...also i^2 = -1

Answer 3

you might want to start with
\[x^2-8ix+5=0\]

Answer 4

So then, do I plug in x^2 - 8ix + 5 into the quadratic equation?

Answer 5

yeah. The answer shouldn't be pretty though.

Answer 6

Ok thanks everybody

Answer 7

You're welcome :)