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Algebra
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4 divided by radical 6 minus radical 2
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\[4\div\sqrt 6-\sqrt 2\]?
yes that is correct
would you mind drawing it out for me?
?
\[4÷\sqrt 6−\sqrt 2=\frac4{\sqrt 6}-\sqrt 2\]\[\qquad=\frac4{\sqrt 6}\times1-\sqrt 2\]\[\qquad=\frac4{\sqrt 6}\times\frac{\sqrt 6}{\sqrt 6}-\sqrt 2\]\[\qquad=\]
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