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find inverse: f(x)= (1/2)^x
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@hartnn @UnkleRhaukus this is what i have: x=2^-y but i don't know how i'll solve for y.
take log on both sides
ok, i'll work out on paper and give answer
i got y= logx/-0,301
it can be simplified as y= \(-\log_2x\) know how ?
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yes wait: logx= -ylog2 logx/-log2= y y= −log2x because of the formula/rule logax= logx/loga and i know the proof thx!
right, welcome ^_^
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