Find the slope‐intercept equation of the line with the following properties:
Perpendicular to the line x- 4y = 2; containing the point (5,2).

Question

Find the slope‐intercept equation of the line with the following properties:
Perpendicular to the line x- 4y = 2; containing the point (5,2).

hartnn · Answer

you have any ideas how to start ?

ash2326 · Answer

@danni2528 Do you know how to find slope of a line from its equation?

anonymous · Answer

Slope-Intercept form is:
y = mx + b
      m is slope
      b is y-intercept
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Change into Slope-Intercept form. 

x - 4y = 2

Subtract x from both sides.

-4y = -x + 2

Divide both sides by -4.

y = 1/4x - 0.5

So you know the slope of this line is 1/4. 

*****The slope of Perpendicular lines is the opposite reciprocal. So the new line will have a slope of -4/1 or -4.
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So far, we have the slope of the new line (-4) and we have a given point (5, 2).

Use Point-Slope formula.
$$y - y1 = m(x - x1) $$$$y - 2 = -4(x - 5) $$Change into Slope-Intercept form.
$$y - 2 = -4(x - 5) $$Distribute.$$y - 2 = -4x + 20$$Add 2 to both sides.$$y = -4x + 22$$^There is your equation for a line perpendicular to x- 4y = 2.