Question

homework 11 please help....

Answer 1

H11P1

a) 1/(RC*C) + RL/L
b) (thats the formula = 1/(2*pi*f)^(2)*L)
c) (thats the formula = 1/(RC*C) + RL/L)
d) (thats the formula = 1/(2*pi*f)^(2)*L)
e) c) (thats the formula = 1/(RC*C) + RL/L)

H11P2

a) (The Formula = vm*0.1)
b) Cs / Rp
c) Cs / Rp
d) 0.1*VM(t)

H11P3
a)C
b)R
c)L
d ?
e) L
f) 1000
g) 1
h ?

Answer 2

H11P3
d) 4

Answer 3

tks

Answer 4

h = 16

Answer 5

@Jose.oliveira2 the formula doesn't work, or I'm doing it wrong.

My values are: L≈0.65mH, RL≈4.0Ω, RC≈490.0kΩ

and the tunning capacitors are: 46.0416895277pF and 17.0912179362pF

could you help me plz?

Answer 6

I have the same values as brunofornari, and I can't get the results to check ...
Any help? Also f=860kHz,
So I guess for H11P1b):
1/(2*pi*f)^(2)*L = 1/(2*pi*860k)^(2)*0.65m= 2.22616175526e-17 = 0.0000261p
am I doing it right?

Answer 7

@Jone133

No.. your question is: 1/(((2*pi*860k)^(2))*0.65m) = 5.26902190593e-11 = 52.6902190593pF