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Mathematics 22 Online
OpenStudy (hba):

Limit question

OpenStudy (hba):

\[\lim_{x \rightarrow \infty}\frac{ x^2+x-2 }{ 4x^3-1 }\]

OpenStudy (hba):

@Zekarias

OpenStudy (hba):

|dw:1352740692965:dw|

OpenStudy (hba):

@hartnn Happy ?

hartnn (hartnn):

divide numerator and denominator by highest power of x that is x^3 here

OpenStudy (hba):

Let me solve :)

hartnn (hartnn):

ok, then put 1/x,1/x^2,1/x^3....... and so on = 0 as x-> infinity all 1/x goes to 0

OpenStudy (hba):

sorry wrong answer lol

hartnn (hartnn):

numerator = ?

OpenStudy (hba):

0

hartnn (hartnn):

yes.

OpenStudy (anonymous):

correct

OpenStudy (hba):

Thank you guys.

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