Question

Please help me :) I appreciate feedback!

Describe the differences between the graph of y = -3(x + 7)2 - 10 and the standard position graph of y = x2.

Answer 1

Well if you graph both functions x^2 and -3(x+7)^2-10 and see the differences. Obviously, from the previous problem you had the vertex is at -7. and the y value from the vertex is at -10 so vertex (-7,-10). The negative in front of the 3 makes the porabola point in the oppoisit direction. Just graph it and see.