Question

2z^2+z-28

Answer 1

(z+4)(2z-7)

Answer 2

it shuld be like this 2z^2+z-28 = 0 right ? @handdavid

Answer 3

2z^2+8z-7z-28

Answer 4

2z(z+8)-7(z+8)=0
(z+8)(2z-7)=0
z+8=0 2z-7=0
z=-8 z=7/2

Answer 5

@handdavid

Answer 6

If you need it to more clear reply back ... Hope that helps :D