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8ab^2x/4a^2b-8ab^2
A;-2bx B;x/4a^2b-1 C;2bx/a-2b
somebody help
@Jonask
why did you write semi colons A: are those values of a b and c
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\[8ab^2x/4a^2b-8ab^2\]
\[\frac{ 8ab^2x }{ 4a^2b-8ab^2 }=\frac{ 2ab^2x }{ a^2b-2ab^2 }\]divide everything by ab
C;2bx/a-2b
yes
so c is an option
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is correct
@tcarroll010
@TuringTest
@Algebraic!
@rob1525
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@hba
@satellite73 I NEED HELP
@gaara438125
correct C
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