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Mathematics 13 Online
OpenStudy (anonymous):

using l'hopitals rule solve lim x-> infinity x^1/x

OpenStudy (zarkon):

what have you tried?

OpenStudy (anonymous):

Is the 1 over x or is it just x over x?

OpenStudy (anonymous):

x^(1/x) or (x^1)/x ?

OpenStudy (anonymous):

If the question is x^(1/x). Look at the posted image below.

OpenStudy (anonymous):

Thanks!

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