Question

write an equation of the sine function with the amplitude and period.

amplitude: 0.5, period: 6pi

Answer 1

2pi/6pi = 1/3 so we have (1/2)sin((1/3)x)

Answer 2

thanks! what is the period for y=-3sin0.5(theta)

Answer 3

how did I get the 1/3? I took the 2p and divided it by the period

Answer 4

no its a completely diff question

Answer 5

so (2pi)/x = 1/2 is what you need to solve.

Answer 6

its the same question in reverse:)

Answer 7

i got 4pi for the second ?