Question

A car traveling at 41 feet per second decelerates at a constant 7 feet per second squared. How many feet does the car travel before coming to a complete stop?

Answer 1

hello, do you know what a first and second derivative is?

Answer 2

I think 41-t^2 and 41t-7t^2

Answer 3

It would be s = 41^2/(2x7)

Answer 4

Thanks

Answer 5

That's as simple as i could get it.

Answer 6

Wow I was making that a lot harder than it needed to be thank you!

Answer 7

Well, the question is hard, but there should be a way to make it very simple. I think this was the simplest.

Answer 8

Thanks!

Answer 9

Yep