What is a cubic polynomial function in standard form with zeros 1, –2, and 2?
(f)x = x^3 + x^2 – 3x + 4
f(x)= x^3 + x^2 – 4x – 2
f(x)= x^3 + x^2 + 4x + 4
f(x)= x^3 – x^2 – 4x + 4

Question

What is a cubic polynomial function in standard form with zeros 1, –2, and 2? 
(f)x = x^3 + x^2 – 3x + 4
f(x)= x^3 + x^2 – 4x – 2
f(x)= x^3 + x^2 + 4x + 4
f(x)= x^3 – x^2 – 4x + 4

anonymous · Answer

Familiar with the Factor-Root theorem?

anonymous · Answer

Or u Can Subs The value of x in the Eq  ie f(x) =0..... (Use Trail or Error)...Method

anonymous · Answer

(x-1)(x+2)(x-2)
multiply them and you should get it

anonymous · Answer

^ ^ also good. Both methods take about the same amount of work.

Factor-Root Theorem: if k is a root (zero) of a function, then (x-k) is a factor.

anonymous · Answer

so I don't know how to multiply them...

anonymous · Answer

Distributive property?

anonymous · Answer

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