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Mathematics 11 Online
OpenStudy (anonymous):

2cosec2xcos2x=cotx-tanx

OpenStudy (anonymous):

[2cosec 2theta cos2theta=cot theta-tan theta]

OpenStudy (anonymous):

cosec2x.cos2x=cos2x/sin2x=LHS RHS=1/2( cosx/sinx-sinx/cosx)=cos2x/sin2x

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