Question

find y'' radical x+ radical y=1

Answer 1

\[\sqrt{x}+\sqrt{y}=1\]

Answer 2

\[x^{\frac{ 1 }{ 2 }}+y^{\frac{ 1 }{ 2 }}=1\]

Answer 3

\[y=(1-x^{\frac{ 1 }{ 2 }})^{2}\]\[y^{'}=2(1-x^{1/2})(-1/2x^{-1/2})\]

Answer 4

y'=\[-\frac{ \sqrt{x} }{ \sqrt{y}}\]

Answer 5

opps the other way around

Answer 6

negative radical y over radical x