Question

12x+19=3

Answer 1

get x by intself

Answer 2

12x+19=3
-19 -19
12x = -16
/12 /12

x = -16/12 = -4/3

Answer 3

Subtract 19 from both sides

Answer 4

\[12x+19=3\] Write original problem.
\[12x + 19-19 = 3-19\] Subtract 19 from both sides.
\[12x=-16\]
\[12x \div12= -16\div12\] Divide 12 from both sides.
\[x=-16/12\]
\[x=-4/3\] Simplify.
\[x=-1\frac{ 1 }{ 3 }\] (as a mixed fraction)