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Mathematics 14 Online
OpenStudy (anonymous):

What is the number of real solutions? –11x2 = x + 11 cannot be determined one solution two solutions no real solutions

OpenStudy (anonymous):

Put the equation in the form ax^2 + bx + c = 0 and take the discriminant which is b^2 - 4ac. If negative, then no real solutions. If 0, then 1real solution. If positive, then 2 real solutions.

OpenStudy (anonymous):

okay thank you!!

OpenStudy (anonymous):

You're welcome!

OpenStudy (anonymous):

wait i just got confused?

OpenStudy (anonymous):

is this right so far? 1^2 -4(-11)(11)

OpenStudy (anonymous):

it has zero solutions? am i right?

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