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OpenStudy (anonymous):
What is the number of real solutions? –11x2 = x + 11 cannot be determined one solution two solutions no real solutions
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OpenStudy (anonymous):
Put the equation in the form ax^2 + bx + c = 0 and take the discriminant which is b^2 - 4ac. If negative, then no real solutions. If 0, then 1real solution. If positive, then 2 real solutions.
OpenStudy (anonymous):
okay thank you!!
OpenStudy (anonymous):
You're welcome!
OpenStudy (anonymous):
wait i just got confused?
OpenStudy (anonymous):
is this right so far? 1^2 -4(-11)(11)
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OpenStudy (anonymous):
it has zero solutions? am i right?
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