A toddler's playground has two slides on either side. The slide on the left is situated at a 45° angle to the ground and is 52 centimeters away from the base of the playground. The slide on the right is positioned at a 30° angle to the ground and is 98 centimeters away from the playground's base. What is the total length of both slides on this playground rounded to the nearest tenth of a centimeter? Type the numeric answer only in the box below. Numerical Answers Expected!
|dw:1352831067571:dw|
h= a/(cos theta)
cos 30 = 98/y and cos 45 = 52/x solve for x and y. Add x + y for answer.
find h for both slides and add the values
im sorry but you both just confused me more than i already was
@tcarroll010 can you explain what you mean?
The slide is the hypotenuse. The flat, horizontal bottom is the measure you are given. The "bottom" divided by the hypotenuse is the cosine of the angle given.
okay....
so how do i find X and Y?
By the equations I gave you.
cos 30 = 98/y so y = 98/cos30
cos 45 = 52/x so x = 52/cos45. Now you have x and y. Now just add them together.
is it 113.2?
That's for y. 113.20
i keep getting 52sqrt2 for x
That's correct!
then how am i suppose to add them?
You have to get the sqrt of 2 in decimal form and then multiply that by 52. You should have a sqrt button on your calculator.
does it look like i have a sqrt button?
|dw:1352833095111:dw|Yes, it looks like this: And to test it, what is the sqrt of 2?
i did it and it said the answer was sqrt2
I don't know how to tell you to enter things on your calculator because I'm not familiar with that model, so 52sqrt(2) = 73.54 = x
i just used my calculator on my computer and it said the answer was 73.32
Maybe you keyed in something wrong, or maybe you truncated the value for sqrt(2), but it is really 73.54. If you use sqrt(2) = 1.41421356 you will get 73.54
is the answer 186.7?
Yes, you got it! Good job!
thank youu
You're welcome!
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