Question

find the zeros of the function
y=(x+2)(x-6)(x-7)

Answer 1

There are three zeros, I'll give you the first one. x=-2, Can you find the rest?

Answer 2

I dont know how to even do this

Answer 3

okay. you pretty much have to solve for x, let me show you how.

Answer 4

ok

Answer 5

Set the following equation equal to zero: y=(x+2)(x-6)(x-7), so (x+2)(x-6)(x-7)=0
so
(x+2)=0
(x-6)=0
(x-7)=0

now solve each one for x.
for the first one, x+2=0, subtract 2 from both sides, x=-2
The same goes for the rest. Let me know what you get.

Answer 6

6 and 7

Answer 7

Yes, x=6, 7, and -2

Answer 8

That's really it.

Answer 9

do you know how to write a polynomial in factored form

Answer 10

Yes.

Answer 11

can you help me with x^3-2x^2-24x and writing it in factored form

Answer 12

Sure thing. So first, start factoring out the x.

Answer 13

x(x-6)(x+4)

Answer 14

ok

Answer 15

From x^3-2x^2-24x, after you factor out an x, you get x^2-2x-24.

Answer 16

so, it looks something like x(x^2-2x-24). Then you factor the inside. In order to factor this, find what number you have to multiply to get 24( the last number), and what numbers you must add to get the inside number(-2)

Answer 17

So if you multiply -6 by 4, you get -24, also if you add these two together you get -2

Answer 18

Does that kinda help?

Answer 19

Yeah thnaks