$6300 is invested, part of it at 10% and part of it at 9%. For a certain year, the total yield is $598.00. How much was invested at each rate.
How much was invested at 10%
How much was invested at 9%

Question

$6300 is invested, part of it at 10% and part of it at 9%. For a certain year, the total yield is $598.00. How much was invested at each rate. 
How much was invested at 10%
How much was invested at 9%

hero · Answer

x = investment 1
y = investment 2

Total Invested Equation:
x + y = 6300

Total Yield Equation:
.10x + .09y = 598.00

Solve the system