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Square root of 72x^2?
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i dont knw how to. explain please?
Do you know what a perfect square is ?
yes, Perfect square is a number that has a rational number as its square root.
\[\sqrt{(72x)^{2}}\] Is this the equation you want to be solved?
If so, \[\sqrt{(72x)^{2}}= 72x\]
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Or is it √72x^2 without the parentheses
yes
Then you need to find a factor of 72 that is a perfect square.
In other words, \[\sqrt{72}= 6\sqrt{2}\] So, \[6\sqrt{2}\approx 8.49\] Therefore \[\sqrt{72x ^{2}}=8.49x\]
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Actually, \[\sqrt{72x ^{2}}\approx 8.49x\]
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