Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

if f(x) = { 2+x , x>=0 2-x , x<0 Find f(f(x)) ?

OpenStudy (anonymous):

@helder_edwin @hartnn @sami-21 @experimentX

OpenStudy (experimentx):

f(x) = |x|+2 f(f(x)) = ||x|+2| + |x| + 2

OpenStudy (helder_edwin):

i agree \[ f(x)=|x|+2 \] but \[ \large f(f(x))=f(|x|+2)=||x|+2|+2 \]

OpenStudy (anonymous):

i did nt get u guys....

OpenStudy (anonymous):

f(f(x)) = fof (x)

OpenStudy (helder_edwin):

yes. that's what i did.

OpenStudy (anonymous):

Can u expl these Stuffs

OpenStudy (helder_edwin):

first \[ \large f(x)=|x|+2 \] do u agree?

OpenStudy (helder_edwin):

well anyway. the x in f(x) is the argument of the function. the letter itself has no meaning, but when u replace it with something u have to do the same in the RHS.

OpenStudy (helder_edwin):

|dw:1352898658928:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!