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A triangle has the following measurements. What is a possible length for the third side? AB = 4, BC = 17, CA = ? 18 5 10 12
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18
can't it possible be 5 as well if 18 is possible ?
im pretty sure @surdawi is correct
no a^2+b^2 =c^2 4^2 + 17^2 = 305; c = 17.5 if we assume that c is the 17 b^2 = c^2 - a^2 b^2 = 17^2 - 4^2 = 273 b = 16.5
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