Question

not understanding how to do this. can someone help?

Write an equation in slope intercept form of the line that passes through (4, 1) and (5, -1).
A. y = -4x + 1
B. y = -1/2 x + 9
C. y = 4x + 1
D. y = -2x + 9

Answer 1

1) Find slope.
\[Slope = \frac{ y2 - y1 }{ x2 - x1 }\]\[Slope = \frac{ -1 - 1 }{ 5 - 4 } = \frac{ -2 }{ 1 } = -2\]
So you have a slope of -2.
You also have a given point.

2) Put into Point-Slope form.
\[y - y1 = m(x - x1) \] Lets use point (4, 1) and the slope of -2.
\[y - 1 = -2(x - 4)\]3) Change into Slope-Intercept form.
\[y - 1 = -2(x - 4)\]Distribute.\[y - 1 = -2x + 8\]Add 1 to both sides.\[y = -2x + 9\]

Slope-intercept form is: \[y = -2x + 9\]

Answer 2

oooh thank you so much for showing me how to do this. i think im getting to know how to do it better now. thank you again!

Answer 3

You're welcome! I'm glad this helped you!(:
Also:\[ \Huge{\color{turquoise}{\mathbb{Welcome \quad To \quad OpenStudy!!}}} \]

Answer 4

yes it truly did help. thank you