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Solve square root of x-3 = square root of 2 subtract square root of x for...x Solutions: a.1/8 b.25/8 c.No solution d.-25/8
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This? \[\sqrt{x-3} = \sqrt{2} - \sqrt{x}\]
yes
start by squaring both sides. So, x-3 = 2 - 2sqrt(2x) + x Then simplify: 2sqrt(2x) = 5 -> sqrt(2x) = 5/2
so is it b? which one is it?
Can you take this last equation and square both sides?
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How? I don't know
Yea I dont know
sqrt(2x) = 5/2 -> 2x = 25 / 4, so x = 25/8
Finally! Thank You
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