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Mathematics 14 Online
OpenStudy (anonymous):

(2x-1)^2=18

OpenStudy (anonymous):

do you know where to start?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

how do you get rid of something squared? square root?

OpenStudy (anonymous):

yes. but you cant square root 18

OpenStudy (anonymous):

just leave it as \[\sqrt{18}\]

OpenStudy (anonymous):

remember its + and - so you'll get 2 answers for x

OpenStudy (anonymous):

which would be?

OpenStudy (anonymous):

(2x-1)^2=18 2x-1=√18 solve this for x 2x-1=-√18 solve this for x

OpenStudy (anonymous):

\[\sqrt{18} -1\] /2

OpenStudy (anonymous):

and (-√18-1)/2

OpenStudy (anonymous):

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