Question

Find the equation of the line tangent to the graph of tanx at x=0.

Answer 1

f'(x)=sec^2(x)

Answer 2

y-tanx=sec^2(x)(x-0)

Answer 3

y=xsec^2(x)+tanx

Answer 4

Where am I going wrong?

Answer 5

y=xsec^2(x)+tanx needs more pie