Question

HEEELPP!!!! The point (x,-1) is 13 units from the point (3,11). What are the possible values of x?
Answer: -2,8

Answer 1

\[(x-3)^2+(-1-11)^2=13^2\] solve for \(x\)

Answer 2

\[(x-3)^2+144=169\]
\[(x-3)^2=25\]
\(x-3=5\) or \(x-3=-5\) etc

Answer 3

how do you find x?

Answer 4

add 3

Answer 5

So it's not 3 to power of 2 then for (x-3)^2?