Algebra
13 Online
OpenStudy (hba):
If 8^y=2 and 3^x+y=81 then x= ?
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OpenStudy (hba):
I got 11/3 ?
OpenStudy (hba):
Right or wrong @kropot72
OpenStudy (anonymous):
2^(3y) = 2^(1)
3y = 1
y = 1/3..
OpenStudy (hba):
I have already solved it and i got 11/3,right or wrong ?
OpenStudy (kropot72):
I get 3.996
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OpenStudy (hba):
@kropot72 LoL :D
OpenStudy (hba):
You could have got 3.66667
OpenStudy (hba):
@waterineyes Yes ?
OpenStudy (hba):
So 11/3 is not the right answer ?
OpenStudy (anonymous):
3^{x+1} = 242
(x+1) log(3) = log(242)
x + 1 = 4.9964
Solve this to get x..
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OpenStudy (kropot72):
\[3^{x}=80\frac{2}{3}\]
\[x \ln 3=\ln 80\frac{2}{3}\]
\[x=\frac{\ln 80.66666}{\ln 3}=3.996\]
OpenStudy (anonymous):
It's 3.9964..
OpenStudy (anonymous):
Go with @kropot72
OpenStudy (anonymous):
If you are confident about x = 11/3 then tell us how did you get that @hba
OpenStudy (hba):
3^x+y=81
3^x+y=3^4
x+y=4
x=4-y
x=4-1/3
x=12-1/3
x=11/3
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OpenStudy (anonymous):
Man that x+y whole is in power???
OpenStudy (hba):
yeah ?
OpenStudy (anonymous):
Is it 3^{x+y} or 3^{x} + y..
OpenStudy (hba):
\[3^{x+y}\]
OpenStudy (anonymous):
Then you are right...
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OpenStudy (hba):
Thanks Alot.
OpenStudy (anonymous):
@hba please use brackets to show properly...
OpenStudy (hba):
@waterineyes Sorry for the confusion.
OpenStudy (anonymous):
It is okay dear...
OpenStudy (kropot72):
Next time please type 3^(x+y). Thanks in advance :)