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(2g - 3) ^3
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same concept as \[(x+4)^{3}\] solve for (2g-3)(2g-3) = 4g^2 -12g + 9 then multiply that answer by (2g-3) again
Otherwise, we have standard formula too...
simplify ( a-b)^3=a^3-b^3-3ab( a-b)
I see how its done, but between you me and the fence post.. Ive no idea how or why... but I thank you for your help.. wish me luck.. next step.. dividing polynomials
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sister r u understand.
\[(a-b)^3 = a^3 - b^3 -3ab(a-b)\] Here : \(a = 2g\) and \(b=3\).. Just plug in the values and solve your question..
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