trying to divide x-4 into x^3-4x^2+4x-16? help!

Question

anonymous · Answer

x^2 + 4
           -------------------
x - 4 / x^3 - 4x^2 + 4x - 16
           x^3 - 4x^2 
          ------------------  -
                         0   +  4x - 16
                                   4x - 16
           --------------------  -
                                      0

the answer is (x^2 + 4)

anonymous · Answer

yea that what i got the actual problem says use the given zero to find remaining zeros...
frunction:  x^3-4x^2+4x-16   given sero is 4    from there i turned it into x-4=0 and thats why i divided....but now with the 4x-16 what do i do???!