Question

i dont get this at all

Answer 1

\[\sqrt{48a ^{3}b ^{2}c ^{5}}+4ac \sqrt{75ab ^{2}c ^{3}}-2c \sqrt{12a ^{3b ^{2}c ^{3}}}\]

Answer 2

Its too much to do. I'll give you a small example.
sqrt[48(a^3)(b^2)(c^5)] = sqrt[(3*4^2)(a*a^2)(b^2)(c^2*c^2*c)]
Now take out all the numbers or variables which are raised to the power 2.
= 4*a*b*c*c*sqrt[3ac] = 4ab(c^2) sqrt[3ac]
Solve it this way.