just point me in right direction please
north.
\[\sqrt{x+6}-x=6\]
l;ol
In this case, it wouldn't be north since you want help with math. sqrt(x+6)-x=6 Since -x does not contain the variable to solve for, move it to the right-hand side of the equation by adding x to both sides. sqrt(x+6)=x+6 To remove the radical on the left-hand side of the equation, square both sides of the equation. (sqrt(x+6))^(2)=(x+6)^(2) Simplify the left-hand side of the equation. x+6=(x+6)^(2) Squaring an expression is the same as multiplying the expression by itself 2 times. x+6=(x+6)(x+6) Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group. x+6=(x*x+x*6+6*x+6*6) Simplify the FOIL expression by multiplying and combining all like terms. x+6=(x^(2)+12x+36) Remove the parentheses around the expression x^(2)+12x+36. x+6=x^(2)+12x+36 Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. x^(2)+12x+36=x+6 Since x contains the variable to solve for, move it to the left-hand side of the equation by subtracting x from both sides. x^(2)+12x+36-x=6 Since 12x and -x are like terms, add -x to 12x to get 11x. x^(2)+11x+36=6 To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side. x^(2)+11x+30=0 In this problem 6*5=30 and 6+5=11, so insert 6 as the right hand term of one factor and 5 as the right-hand term of the other factor. (x+6)(x+5)=0 Set each of the factors of the left-hand side of the equation equal to 0. x+6=0_x+5=0 Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides. x=-6_x+5=0 Set each of the factors of the left-hand side of the equation equal to 0. x=-6_x+5=0 Since 5 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 5 from both sides. x=-6_x=-5 The complete solution is the set of the individual solutions. x=-6,-5
Pointing you in the right direction: Go right instead of left
@zordoloom, you shouldn't copy and paste things from bagatrix
@Hero it explained the process, or not?
For one thing, it's plaigarism. Secondly, it is not your own work. Thirdly, it provides way too many steps and should not be used for teaching.
Always check your solutions; I don't think the solution x=6 meets the specification of the problem.
x=-6
Clearly not reading well enough today....
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