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OpenStudy (anonymous):
|r + 3| ≥ 7
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OpenStudy (anonymous):
when you take the abs value
r + 3 ≥ 7 or r + 3 ≥ -7
solve for r
OpenStudy (anonymous):
do i add i 3 to 7?
OpenStudy (anonymous):
u have +3
so you will have to subtract
OpenStudy (anonymous):
so that's 4?
OpenStudy (anonymous):
r + 3 ≥ 7
-3 -3
r ≥ 4......correct
now solve the other one
r + 3 ≥ -7
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OpenStudy (anonymous):
ugh ok
OpenStudy (anonymous):
lol come on with absolute values you get two solutions
|x| = |-x| = x
OpenStudy (anonymous):
i got 10 r > 10
OpenStudy (anonymous):
nope
show me what you did
OpenStudy (anonymous):
r + 3 ≥ \(\huge{\color{red}{\text{-}}}\)7
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OpenStudy (anonymous):
mmmm
OpenStudy (anonymous):
uhhhhhh
OpenStudy (anonymous):
so - 3 to 7
OpenStudy (anonymous):
r > -4????????????????????????????????????
OpenStudy (anonymous):
r + 3 ≥ -7
subtract a 3 from both sides
r + 3 -3 ≥ -7 -3
r ≥ -10
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OpenStudy (anonymous):
=(
OpenStudy (anonymous):
i said 10
OpenStudy (anonymous):
oh wait i forgot the - sign opps
OpenStudy (anonymous):
thats y i marked it in red :p
OpenStudy (anonymous):
i did this problem 5x + 13= -7
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OpenStudy (anonymous):
i added 13 to both sides
OpenStudy (anonymous):
ok show me step by step so i can tell you where you make mistakes
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
|dw:1353030553162:dw|
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