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Mathematics 14 Online
OpenStudy (anonymous):

|r + 3| ≥ 7

OpenStudy (anonymous):

when you take the abs value r + 3 ≥ 7 or r + 3 ≥ -7 solve for r

OpenStudy (anonymous):

do i add i 3 to 7?

OpenStudy (anonymous):

u have +3 so you will have to subtract

OpenStudy (anonymous):

so that's 4?

OpenStudy (anonymous):

r + 3 ≥ 7 -3 -3 r ≥ 4......correct now solve the other one r + 3 ≥ -7

OpenStudy (anonymous):

ugh ok

OpenStudy (anonymous):

lol come on with absolute values you get two solutions |x| = |-x| = x

OpenStudy (anonymous):

i got 10 r > 10

OpenStudy (anonymous):

nope show me what you did

OpenStudy (anonymous):

r + 3 ≥ \(\huge{\color{red}{\text{-}}}\)7

OpenStudy (anonymous):

mmmm

OpenStudy (anonymous):

uhhhhhh

OpenStudy (anonymous):

so - 3 to 7

OpenStudy (anonymous):

r > -4????????????????????????????????????

OpenStudy (anonymous):

r + 3 ≥ -7 subtract a 3 from both sides r + 3 -3 ≥ -7 -3 r ≥ -10

OpenStudy (anonymous):

=(

OpenStudy (anonymous):

i said 10

OpenStudy (anonymous):

oh wait i forgot the - sign opps

OpenStudy (anonymous):

thats y i marked it in red :p

OpenStudy (anonymous):

i did this problem 5x + 13= -7

OpenStudy (anonymous):

i added 13 to both sides

OpenStudy (anonymous):

ok show me step by step so i can tell you where you make mistakes

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

|dw:1353030553162:dw|

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