Question

The perimeter of a rectangular lot is 32 meters. The length exceeds the width by 4 meters. Find the length of the lot.
Answer

6 m

14 m

10 m

18 m

Answer 1

P=2l+2w

Answer 2

l=w+4 because it exceeds the width by 4 aka w+4

Answer 3

I got 14.

Answer 4

its actually 6

Answer 5

ill set it all up one sec

Answer 6

\[32=2(w+4)+2w \]
\[32=2w+8+2w\]
\[32=4w+8\]
\[24=4w\]
\[w=6\]

Answer 7

you know that the length=w+4 that is why you plug it in for l

Answer 8

@ramirokool makes sense?

Answer 9

Yes