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whats the vertex of f(x)=x^2-2x-8
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change it to the completed square form... can u?
no
the first coordinate of the vertex is alway \(-\frac{b}{2a}\) in your case it is \(-\frac{-2}{2\times 1}=1\) the second coordinate of the vertex is what you get when you replace \(x\) by that number
1^2-2(1)-8=...
the completed square form is a(x-h)^2+k
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try to take it to that form
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