Pleaseeeee help
How many liters of 75% solution should be mixed with a 55% solution to get 70 liters of 63% solution? How many liters of the 55% and 75% solutions should be used?

Question

Pleaseeeee help
How many liters of 75% solution should be mixed with a 55% solution to get 70 liters of 63% solution? How many liters of the 55% and 75% solutions should be used?

anonymous · Answer

first you need 63% of 70 which is $.63\times 70=44.1$

anonymous · Answer

then put $x$ as the amount of 75% solution, making $70-x$ the amount of 55% solution and solve 
$$.75x+.55(70-x)=44.1$$ for $x$

anonymous · Answer

probably easier to get rid of the decimals and solve 
$$75x+55(70-x)=4410$$