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Mathematics 18 Online
OpenStudy (anonymous):

160=x^2+2x*2

OpenStudy (anonymous):

160=x(x+4) (x+2)^2=164 x=\[\pm2(1+\sqrt{41})\]

OpenStudy (anonymous):

am sorry I wrote my question wrong it find the volume of the box .volume is 160 find lenght x+2 width x height 2 so am guesiing that you will write it 160=(x+2)*x*2

OpenStudy (anonymous):

160=2x(x+2) 80=x(x+2) x=8:)

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