Question

Factor: 27x4-12(xcubed)-36/(xcubed) please and thank you :)

Answer 1

\[27x ^{4}-12\sqrt[3]{x}-36/\sqrt[3]{x}\]

Answer 2

Is that \(x^3\) or \(\sqrt[3]{x}\) ??

Answer 3

\[\sqrt[3]{x} :)\]

Answer 4

let \[\sqrt[3]{x}\] be a

Answer 5

and then how do I factor the 36/a along with the rest of the equation?

Answer 6

\[a^{12}-12a-\frac{ 36 }{ a }\]

Answer 7

\[a^{13}-12a^{2}-36\]

Answer 8

what happened to the 27x^4?

Answer 9

\[x^{4}= \sqrt[3]{x}^{12}\]

Answer 10

after y^13-12y^2-36 what should i do?

Answer 11

try to factor out then for the roots you find put \[\sqrt[3]{x} \] instead of y

Answer 12

and then what? D:

Answer 13

sorry i don't really know anything

Answer 14

did you find the roots

Answer 15

im unsure of what that means

Answer 16

for example a^2-2a-1=(a-1)(a-1) then the root is a=1